Question

In ΔOPQ, p = 38 cm, q = 29 cm and ∠O=39°. Find the length of o, to the nearest centimeter.

Answer 1

Use law of cosines

o^2=p^2+q^2-2pqCos(C)

o^2=38^2+29^2-38*29Cos(39)

o^2=1444+841-1712.83

o^2=572.17

o=23.92

Say 24 cm