Answer:
Step-by-step explanation:
Let's solve your system by substitution.
5x+3y=35;2x+4y=28
Step: Solve 5x+3y=35 for x:
5x+3y=35
5x+3y+−3y=35+−3y(Add -3y to both sides)
5x=−3y+35
5x/ 5 = −3y+35/ 5 (Divide both sides by 5)
Step: Substitute −3/ 5 y+7 for x in 2x+4y=28:
2x+4y=28
2( −3/ 5 y+7)+4y=28
14/ 5 y+14=28 (Simplify both sides of the equation)
14/ 5 y+14+−14=28+−14 (Add -14 to both sides)
14/ 5 y=14
14/ 5 y/ 14/ 5 = 14/ 14/ 5
(Divide both sides by 14/5)
y=5
Step: Substitute 5 for y in x= −3/ 5 y+7:
x= −3/ 5 y+7
x= −3/ 5 (5)+7
x=4 (Simplify both sides of the equation)
Answer:
x=4 and y=5
