question isn't clear but I believe you are asking for the area of triangle ABC given sides a, b, c
We use the example question:
Find the area (in square units) of the triangle described.
a = 49mm, b = 33mm, c = 18mm
Answer and explanation:
We apply Heron's formula to solve the area of a triangle given the sides of the triangle a, b, c
A= √s(s-a)(s-b)(s-c)
Where A = area of triangle in square units
s= semiperimeter(a+b+c/2) of a triangle
a, b, c= lengths of the sides of the triangle
Therefore area of triangle =√50(50-49)(50-33)(50-18)
= √27200
=164.92mm²
