Answer:
[tex] \triangle FDE \cong \triangle RTS[/tex]
Step-by-step explanation:
[tex] In \:\triangle FDE \:\&\:\triangle RTS[/tex]
[tex] FD \cong RT... (given) [/tex]
[tex] \angle FDE \cong \angle RTS... (given)[/tex]
[tex] DE \cong TS... (given) [/tex]
[tex] \therefore \triangle FDE \cong \triangle RTS\\(by\: SAS\: postulate)[/tex]