Question

A child riding a bicycle at 5 meters per seconds accelerates at 2.0 meters per second for 4.0 seconds. What is the child's speed at the end of this 4.0 second interval

Answer 1

Explanation:

Using Kinematics,

We have v = u + at.

=> v = (5m/s) + (2.0m/s²)(4.0s)

=> v = 13m/s.

Hence the child's speed is now 13m/s.

Answer 2

Answer:

13 m/s

Explanation:

Key:

Vi = 5.0 m/s

A  = 2.0 m/s^2

T  = 4.0 s

X = (5m/s) + (2.0m/s/s) (4.0s)

 X = 13m/s.