Question

A roller coaster has a velocity of 25 m/s at the bottom of the first hill. How high was the hill?
PLEASE HELP

Answer 1

Answer:

The height of the hill is "31.85 m".

Explanation:

The given value is:

Velocity,

v = 25 m/s

As we know,

⇒ $Kinetic \ energy =Potential \ energy$

i.e,

⇒ $mgh=\frac{1}{2} mv^2$

⇒    $gh=\frac{1}{2} v^2$

⇒      $h=\frac{v^2}{2g}$

On substituting the given value, we get

⇒      $h=\frac{(25)^2}{2\times 9.81}$

⇒         $=\frac{625}{19.62}$

⇒         $=31.85 \ m$

Answer 2

The height of the hill will be "31.85 m".

Given;

• Velocity, v = 25 m/s

We know the relation,

→ $Kinetic \ energy (K.E) = Potential \ energy (P.E)$

or,

→ $mgh = \frac{1}{2}mv^2$

or,

→    $gh = \frac{1}{2}v^2$

         $h = \frac{v^2}{2g}$

By putting the values, we get

            $= \frac{(25)^2}{2\times 9.81}$

            $= \frac{625}{19.62}$

            $= 31.85 \ m$

Thus the response above is right.

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