Question

An aerial photographer who photographs real estate properties has determined that the best photo is taken at a height of approximately 483 ft and a distance of 858 ft from the building. What is the angle of depression from the plane to the building?​

Answer 1

Answer:

x = distance from the building = 837 ft

y = height = -483 ft (The building is DOWN from the plane.)

θ = angle of depression = to be determined

tan θ = y/x

tan θ = -0.577060932

θ = arctan (-0.577060932)

θ = -29.98756509 ° ≈ -30 ° (The building is DOWN from the plane.)

Step-by-step explanation:

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Answer 2

The answer is "$34^{\circ}$".

Given:

Opposite= 483 ft

Hypotenus= 858 ft

To find:

The angle of depression=?

Solution:

• Since they are alternative inner angles, the angles of altitude and depression are equal. Within right-angle triangular, we obtain opposite=483 and hypotenus=858.
• So, to use a trigonometric ratio, we get

               $\to \sin \theta =\frac{opposite}{hypotenus} \\\\ \to \sin \theta =\frac{483}{858} \\\\\to \theta = \sin^{-1} (\frac{483}{858}) \\\\\to \theta \approx 34.25^{\circ}$

• An angle of dip from the plane to the building is $34^{\circ}$

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