Respuesta :

Answer:

Centroid of ΔABC = (4,2)

Step-by-step explanation:

Explanation:-

Given points are A(0,6) , B(2,0) and C(10,0)

Centroid of ΔABC

        = [tex](\frac{x_{1}+x_{2} +x_{3} }{3} ,\frac{y_{1}+y_{2} +y_{3} }{3})[/tex]  

      =    [tex](\frac{0+2+10}{3} , \frac{6+0+0}{3} )[/tex]

     = [tex](\frac{12}{3} , \frac{6}{3} )[/tex]

     = (4 , 2)

Centroid of ΔABC = (4,2)

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