Question

An artificial satellite orbits Earth at a speed of 7800 m/s and a height of 200 km above Earth’s surface. The satellite experiences an acceleration due to gravity of

A39 m/s2
Bless than 39 m/s2 but greater than 9.8 m/s2
C9.8 m/s2
Dless than 9.8 m/s2 but greater than zero

Answer 1

Answer: less than 9.8 m/s^2 but greater then zero

Explanation:

Gravitation law

Answer 2

The gravitational acceleration experienced by the satellite is 9.26m/s².

Therefore, Option D) less than 9.8 m/s2 but greater than zero is the correct answer.

Given the data in the question;

• Speed or Velocity of the artificial satellite; $v = 7800m/s$

• Height of satellite above the Earth; $h = 200km = 200000m$

To keep the satellite in orbit, a centripetal force is required, this is provided by the gravitational force.

Hence, $F_{centripetal } = F_{gravity}$

That is; $\frac{mv^2}{r} = mg$

divide both sides by "m"

$\frac{v^2}{r} = g$

Here, v is the velocity, g is the gravitational acceleration experienced by the satellite, r is the distance of the satellite from the center of the EARTH.

Diameter of the Earth; $D_{Earth} = 12742 km = 12742000m$

Radius of the Earth; $R_{Earth} = \frac{12742000m}{2} = 6371000m$

So,

Distance of the satellite from the center of the EARTH; $r = R_{Earth} + h = 6371000m + 200000m = 6571000m$

 

Now we substitute our values into the equation

$\frac{v^2}{r} = g$

$g = \frac{(7800m/s)^2}{6571000m} \\\\g = \frac{60840000m^2/s^2}{6571000m}\\\\g = 9.26m/s^2$

The gravitational acceleration experienced by the satellite is 9.26m/s².

Therefore, Option D) less than 9.8 m/s2 but greater than zero is the correct answer.

Learn more; https://brainly.com/question/7282772