BY ANSWERING THIS QUESTION UR PUTTING IT ON UR MOM's LIFE THAT U WON'T STEAL MY POINTS.

5) Choose the best answer.

Using Gay-Lussac's Law, calculate the new temperature in the following situation.

A sample of gas has a pressure of 3.50 atm and a temperature of 22°C. If the pressure decreases to 1.75 atm, what will be its Celsius temperature if the volume remains constant?

125.5* C
-125.5* C
-147.5* C
-195* C
195* C

6) Choose the best answer.

Using Gay-Lussac's Law, calculate what the new pressure in the following situation.

A tank of acetylene sits on the back of a truck. During the afternoon, the temperature of a gas has reached 38°C (311 K) with a pressure of 508 kPa. That night, the temperature drops to 29°C (302 K). Since the gas was in a metal tank, the volume remained constant. What is the new pressure?

308 kPa
500 kPa
493 kPa
503 kPa
311 kPa

Respuesta :

Answer:

[tex]T_2=-125.58\°C[/tex]

Explanation:

Hello!

In this case, considering the Gay-Lussac's law which describes the pressure-temperature behavior as a directly proportional relationship by holding the volume as constant, we write:

[tex]\frac{T_1}{P_1} =\frac{T_2}{P_2}[/tex]

Whereas solving for the final temperature T2, we get:

[tex]T_2=\frac{T_1P_2}{P_1}[/tex]

Thus, we plug in the given data (temperature in Kelvins) to obtain:

[tex]T_2=\frac{(22+273.15)K*1.75atm}{3.50atm} \\\\T_2=147.58K-273.15\\\\T_2=-125.58\°C[/tex]

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