Answer:
[tex]x = 50[/tex]
[tex]y = 25[/tex]
Step-by-step explanation:
[tex] \sin(60) = \frac{opposite}{hypotenuse} [/tex]
[tex] \sin(60) = \frac{25 \sqrt{3} }{x} [/tex]
[tex](x) \sin(60) = \frac{25 \sqrt{3} }{x} (x)[/tex]
[tex](x) \sin(60) = 25 \sqrt{3} [/tex]
[tex] \frac{(x) \sin(60) }{ \sin(60) } = \frac{25 \sqrt{3} }{ \sin(60) } [/tex]
[tex]x = \frac{25 \sqrt{3} }{ \sin(60) } [/tex]
[tex]x = 50[/tex]
[tex] \tan(60) = \frac{opposite}{adjacent} [/tex]
[tex] \tan(60) = \frac{3 \sqrt{25} }{y} [/tex]
[tex](y) \tan(60) = \frac{25 \sqrt{3} }{y} (y)[/tex]
[tex](y) \tan(60) = 25 \sqrt{3} [/tex]
[tex] \frac{(y) \tan(60) }{ \tan(60) } = \frac{25 \sqrt{3} }{ \tan(60) } [/tex]
[tex]y = \frac{25 \sqrt{3} }{ \tan(60) } [/tex]
[tex]y = 25[/tex]
