Respuesta :

3x+2y-4z=12 add 4z on both sides 
3x+2y=12+4z  subtract 2y on both sides 
3x=12+4z-2y divide 3 on both sides 
x= 4+4/3z-2/3y 
x= 4+1.25z-.67y

3x+2y-4z=12 subtract 3x on both sides 
2y-4z=12-3x  add 4z to both sides 
2y=12-3x+4z divide 2 on both sides 
y=6-3/2x+4/2z 
y=6- 1.5x+2z 

3x+2y-4z=12 subtract 3x on both sides 
2y-4z=12-3x subtract 2y on both sides 
-4z=12-3x-2y divide by -4 on both sides 
z=-3-3/4x-2/4y 
z=-3-.75x-.5y  

your welcome you can do the other one 

ACCESS MORE
EDU ACCESS
Universidad de Mexico