3x+2y-4z=12 add 4z on both sides
3x+2y=12+4z subtract 2y on both sides
3x=12+4z-2y divide 3 on both sides
x= 4+4/3z-2/3y
x= 4+1.25z-.67y
3x+2y-4z=12 subtract 3x on both sides
2y-4z=12-3x add 4z to both sides
2y=12-3x+4z divide 2 on both sides
y=6-3/2x+4/2z
y=6- 1.5x+2z
3x+2y-4z=12 subtract 3x on both sides
2y-4z=12-3x subtract 2y on both sides
-4z=12-3x-2y divide by -4 on both sides
z=-3-3/4x-2/4y
z=-3-.75x-.5y
your welcome you can do the other one