Help! help! help! Find the lengths of the legs

Answer:
2[tex]\sqrt{2}[/tex]
Step-by-step explanation:
sin45=[tex]\frac{x}{4}[/tex] ( sin is opposite over hypotenuse )
multiply
4sin45=[tex]2\sqrt{2}[/tex]
cos45=[tex]\frac{x}{4}[/tex] ( cos is adjacent over hypotenuse )
multiply
4cos45= 2[tex]\sqrt{2}[/tex]
tip: in a 45-45-90 triangle, the sides are equivalent.