Question

PLEASE HELPP
What is the solution to the following system of equations?

x − 3y = 6
2x + 2y = 4

(-1, 3)
(3, -1)
(1, -3)
(-3, 1)

Answer 1

Answer:

The solution to the system of equations be:

$x=3,\:y=-1$

Hece, option B is correct.

Step-by-step explanation:

Given the system of equations

$\begin{bmatrix}x-3y=6\\ 2x+2y=4\end{bmatrix}$

Multiply x − 3y = 6 by 2:      2x-6y=12

$\begin{bmatrix}2x-6y=12\\ 2x+2y=4\end{bmatrix}$

so

$2x+2y=4$

$-$

$\underline{2x-6y=12}$

$8y=-8$

so the system of equations becomes

$\begin{bmatrix}2x-6y=12\\ 8y=-8\end{bmatrix}$

Solve 8y = -8 for y

$8y=-8$

Divide both sides by 8

$\frac{8y}{8}=\frac{-8}{8}$

$y=-1$

$\mathrm{For\:}2x-6y=12\mathrm{\:plug\:in\:}y=-1$

$2x-6\left(-1\right)=12$

$2x+6=12$

subtract 6 from both sides

$2x+6-6=12-6$

$2x=6$

Divide both sides by 2

$\frac{2x}{2}=\frac{6}{2}$

$x=3$

Therefore, the solution to the system of equations be:

$x=3,\:y=-1$

Hence, option B is correct.

Answer 2

A N S W E R :

• x - 3y = 6 ......[Equation (i) ]
• 2x + 2y = 4 ......[Equation (ii)]

⚽ From Equation (i) we get :

• x = 6 + 3y......[Equation (iii)]

⚽ Now, Substitute the equation (iii) in equation (ii) we get :

→ 2(6 + 3y) + 2y = 4

→ 12 + 6y + 2y = 4

→ 8y = 4 - 12

→ 8y = -8

→ y = -8 ÷ 8

→ y = -1

⚽ Now Substituting value of y = -1 in equation (iii) we get :

→ x = 6 + 3y

→ x = 6 + 3(-1)

→ x = 6 + (-3)

→ x = 6 - 3

→ x = 3

• Hence,the value of x = 3 and value of y = -1.