Question

Given that X
${x}^{3}$
x
${3}^{3}$
=
${6}^{3}$
, find the value of X.​

Answer 1

Answer:

$x = 2$

Step-by-step explanation:

$x^{3} * 3^{3} = 6^{3}$

$=> (3x)^{3} = 6^{3}$

$=> 3x = \sqrt[3]{6^{3}} = 6$

$=> x = \frac{6}{3} = 2$

Answer 2

Answer:

${x}^{3} \times {3}^{3} = {6}^{3} \\ take \: cube \: root \: on \: both \: side \ \\ \sqrt[3]{ {x}^{3} } \times \sqrt[3]{ {3}^{3} } = \sqrt[3]{ {6}^{3} } \\ x \times 3 = 6 \\ x = \frac{6}{3} \\ x = 2 \\ thnk \: you$