Answer:
0 / no solutions
Step-by-step explanation:
Rewrite both in terms to the form y = equation.
EQ1: y = 3x + 4 (already in correct form)
EQ2: y = 3x - 6 (subtracting 6 from both sides).
Now suppose there is an intersection, then:
3x + 4 = 3x - 6, subtracting 3x from both sides gives:
4 = -6, which is a contradiction!
Therefore there are 0 / no solutions
