Respuesta :
[tex] \qquad \qquad \qquad \frac{1}{x} + \frac{3}{x } = 16[/tex]
This is how to solve your problem:
- Combine fracrions with common denominator
[tex] \qquad \qquad \frac{1}{x} + \frac{3}{x} = 16[/tex]
[tex] \qquad \qquad \frac{1 + 3}{ x} = 16[/tex]
- Add the numbers
[tex] \qquad \qquad \qquad\frac{1 + 3}{x} = 16[/tex]
[tex] \qquad \qquad\frac{4}{x} = 16 [/tex]
- Multiply all terms by the same value to eliminate fraction denominators
[tex] \qquad \qquad \qquad \color{skyblue}{ \frac{4}{x} = 16}[/tex]
[tex] \qquad \qquad \qquad \color{gold}{x .\frac{4}{x} = x.16}[/tex]
- Cancel multiplied terms that are denominator
[tex] \qquad \qquad \: x.\frac{4}{x} = x.16 [/tex]
[tex] \qquad \qquad 4 = x.16[/tex]
- Re-order terms so constants are on the left
[tex] \qquad \qquad4 = x.16[/tex]
[tex] \qquad \qquad 4 = 16x[/tex]
- Divide boths sides by the same factor
[tex] \qquad \qquad4 = 16x[/tex]
[tex] \qquad \qquad\frac{4}{16} = \frac{16x}{16} [/tex]
- Simplify
- divide the numbers
- Cancel terms that are in both the numerator and denominator
- Move the variable to the left
[tex] \qquad \qquad x = \frac{1}{4} [/tex]
the final answer is :
[tex]x = \frac{1}{4} [/tex]