Options:
[tex]A.\ (\frac{3}{2}, \frac{9}{2})[/tex]
[tex]B.\ (-1, 1)[/tex]
[tex]C.\ (4, 16)[/tex]
[tex]D.\ (\frac{1}{2}, \frac{1}{4})[/tex]
Answer:
[tex]A.\ (\frac{3}{2}, \frac{9}{2})[/tex]
Step-by-step explanation:
Given
[tex]y = x^2[/tex]
Required
Determine which of the given points is not true
[tex]A.\ (\frac{3}{2}, \frac{9}{2})[/tex]
Here
[tex]x = \frac{3}{2}[/tex] and [tex]y = \frac{9}{2}[/tex]
Substitute these values in [tex]y = x^2[/tex]
[tex]\frac{9}{2} = (\frac{3}{2})^2[/tex]
[tex]\frac{9}{2} = \frac{3}{2}*\frac{3}{2}[/tex]
[tex]\frac{9}{2} \ne \frac{9}{4}[/tex]
Both sides of the equation are not equal. Hence, this point do not line on the curve
[tex]B.\ (-1, 1)[/tex]
Here
[tex]x = -1[/tex] and [tex]y = 1[/tex]
Substitute these values in [tex]y = x^2[/tex]
[tex]1 = (-1)^2[/tex]
[tex]1=1[/tex]
Both sides of the equation are equal. Hence, this point line on the curve
[tex]C.\ (4, 16)[/tex]
Here
[tex]x = 4[/tex] and [tex]y = 16[/tex]
Substitute these values in [tex]y = x^2[/tex]
[tex]16 = 4^2[/tex]
[tex]16 = 16[/tex]
Both sides of the equation are equal. Hence, this point line on the curve
[tex]D.\ (\frac{1}{2}, \frac{1}{4})[/tex]
Here
[tex]x = \frac{1}{2}[/tex] and [tex]y = \frac{1}{4}[/tex]
Substitute these values in [tex]y = x^2[/tex]
[tex]\frac{1}{4} = (\frac{1}{2})^2[/tex]
[tex]\frac{1}{4} = \frac{1}{2}*\frac{1}{2}[/tex]
[tex]\frac{1}{4} = \frac{1}{4}[/tex]
Both sides of the equation are equal. Hence, this point line on the curve
From the calculations above; only [tex]A.\ (\frac{3}{2}, \frac{9}{2})[/tex] do no lie on the curve
