Answer:
x is equal to both 3 and 6.
Step-by-step explanation:
[tex]\sqrt{x - 2} + 4 = x\\\sqrt{x - 2} = x - 4\\x - 2 = (x - 4)^2\\x - 2 = x^2 - 8x + 16\\x^2 - 9x + 18 = 0\\(x - 3)(x - 6) = 0\\[/tex]
So x values of 3 and 6 will make this statement true.