Respuesta :

Answer:

x is equal to both 3 and 6.

Step-by-step explanation:

[tex]\sqrt{x - 2} + 4 = x\\\sqrt{x - 2} = x - 4\\x - 2 = (x - 4)^2\\x - 2 = x^2 - 8x + 16\\x^2 - 9x + 18 = 0\\(x - 3)(x - 6) = 0\\[/tex]

So x values of 3 and 6 will make this statement true.

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