Question

A vertical tube 1.34 m long is open at the top.It is filled with 44.2 cm of water.If the speed of sound is 344 m/s, what willthe fundamental resonant frequency be

Answer 1

Answer:

the fundamental resonant frequency is 95.76 Hz

Explanation:

The computation of the fundamental resonant frequency be is given below:

= 1.34 m - 0.442 m

= 0.898 m

Now

$L = \frac{\lambda}{4} \\\\\lambda = 4L$

Now the fundamental resonant frequency is

$f = \frac{V}{\lambda} \\\\= \frac{V}{4L}\\\\= \frac{344}{4\times 0.898}$

= 95.76 Hz

hence, the fundamental resonant frequency is 95.76 Hz