The external and the internal radius of a cylindrical pipe of length 50 cm are 3 cm and 2.6cm respectively. find the volume of material contained by the pipe​

Respuesta :

Answer:351.86 cc( approximately)

Step-by-step explanation:

The volume of the material = External volume - internal volume

= π3^2×50-π 2.6^2×50

=351.86

The volume of the material by the pipe is 351.86 cc.

What is the volume of a cylinder?

The volume of a cylinder is equal to the product of the area of the circular base and the height of a cylinder. The volume of a cylinder is defined as the space occupied by the cylinder as the volume of any three-dimensional shape is the space occupied by it

V = πr²h

where 'r' is the radius of the base (circle) of the cylinder

'h' is the height of the cylinder

Given that the external and the internal radius of a cylindrical pipe are 3 cm and 2.6cm respectively

The length of the pipe is 50 cm

External volume = π(3)²×50 = 1413.71 cc

internal volume = π (2.6)²×50 = 1061.85

The volume of the material = External volume - Internal volume

The volume of the material = 1413.71 - 1061.85

The volume of the material = 351.86 cc

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