Question

What is the percent of Cr in
Cr203?
(Cr = 52.00 amu, O = 16.00 amu)
[?]%

Answer 1

Answer:

68.42%

Step-by-step explanation:

We need to find the percent of Cr in $Cr_2O_3$.

Mass of Cr = 52 amu

Mass of O = 16 amu

Firstly, we will find the molar mass of $Cr_2O_3$ as follows :

M = 2(52) + 3(16)

M = 152 amu

Percent of Cr in  $Cr_2O_3$ will be :

$Cr=\dfrac{2\times 52}{152}\times 100\\\\=68.42\%$

Hence, the required percentage is 68.42%.