Question

A gas has a volume of 5.0 L at a pressure of 50 kPa.Solve for V2 when temperature is held constant and the pressure is increased to 125 kPa.

a. 12.5 L
b. 0.2 L
c. 2.0 L
d. 1250.0 L

Answer 1

Given:
P1 = 50 kPa
V1 = 5.0 L
P2 = 125 kPa
V2 = ?

Boyle's Law

P1V1 = P2V2
50 * 5 = 125 * V2
250 = 125 * V2
250 / 125 = V2
2 = V2

Answer is letter C. 2.0 L

Answer 2

Answer:

c. 2.0 L

Explanation:

According to Boyle's Law, for a gas at constant temperature the product of its volume and pressure remains the same even as these two values vary. That is:

$P_{1}V_{1}  =P_{2} V_{2} \\\\5.0L * 50 kPa = V_{2}* 125 kPa\\ \\V_{2} = 2 L$