Question

Using a launch speed of 40.0 m/s and any angle between 0 and 90 degrees, what would be the largest possible range for a projectile?

its 45

Answer 1

Answer:

The largest possible range of the projectile is 163.27 m.

Explanation:

Given;

launch speed, u = 40 m/s

angle of projection, θ; between 0⁰ and 90⁰

The range of a projection is given as;

$R = \frac{u^2sin(2\theta )}{g}$

The largest possible range will occur at 45 degrees angle of projection;

$R = \frac{u^2sin(2\theta )}{g} \\\\R = \frac{(40)^2sin(2\ \times \ 45^0 )}{9.8}\\\\R = \frac{(40)^2sin( 90^0 )}{9.8}\\\\R = \frac{(40)^2( 1 )}{9.8} \\\\R = 163.27 \ m$

Therefore, the largest possible range of the projectile is 163.27 m.