Answer:
(a) Kinetic energy of the cart is 648.32 J.
(b) Speed of the cart is 11.44 m/s.
Explanation:
From the attached below figure we came to know that,
Mass of the crate is 10 kg (m)
Initial speed of the crate is 1.2 m/s (v)
Coefficient of friction on a rough plane is 0.286 (µ)
Force on the cart is 150 N (F)
The distance which crate is moved (d) is 8.05 m.
Calculation of kinetic energy:
Acceleration of the cart:
We know that,
F = F – m × g × sinθ - µ × m × g × cosθ (F = ma)
m × a = F – m × g × sinθ - µ × m × g × cosθ
10 × a = 150 – (10 × 9.8 × sin 27) – (0.286 × 10 × 9.8 × cos 27)
10 × a = 150 – 44.49 – 24.97
10 × a = 80.54
Calculation of speed:
Change in kinetic energy = m × a × d
Change in kinetic energy = 10 × 8.054 × 8.05
Change in kinetic energy = 648.32 J
Explanation:
