Question

Compute the value of the discriminant and give the number of real solutions to the quadratic equation:
3x^2 - 7x + 9 = 0

Answer 1

$ax^2+bx+c=0$
$3x^2-7x+9=0$
a=3 b=-7 c=9
$\Delta=b^2-4ac=(-7)^2-4*3*9=49-108=-59$
$\Delta<0$
If the delta is less than zero and if no polynomial real roots

Answer 2

$3x^2 - 7x + 9 = 0 \\ \\a=3, \ \ b=-7, \ \ c= 9 \\ \\ \Delta =b^2-4ac = 7^2 -4\cdot 3 \cdot 9 = 49-108= -59 \\ \\ If \ \Delta <0, \ then \ roots \ are \ imaginary \ (non-real)$