Answer:
Step-by-step explanation:
[tex](\frac{\sqrt{3}}{3} +\frac{\sqrt{3}}{2} i)^2\\=\frac{3}{9} +\frac{3}{4} i^2+2 *\frac{\sqrt{3}}{3} *\frac{\sqrt{3}}{2} i\\=\frac{1}{3} -\frac{3}{4} +i\\=\frac{4-9}{12} +i\\=-\frac{5}{12} +i\\[/tex]
[i²=-1]
which is of the form a+bi
where a=-5/12,b=1
