Given:
The midpoint of segment AB has the coordinates M(-4,2).
The coordinates of endpoint A are (-6, -7).
To find:
The coordinates of B.
Solution:
Let the coordinates of point B are (a,b).
Formula for midpoint:
[tex]Midpoint=\left(\dfrac{x_1+x_2}{2},\dfrac{y_1+y_2}{2}\right)[/tex]
The midpoint of segment AB has the coordinates M(-4,2), so by using the above formula we get
[tex]M=\left(\dfrac{-6+a}{2},\dfrac{-7+b}{2}\right)[/tex]
[tex](-4,2)=\left(\dfrac{-6+a}{2},\dfrac{-7+b}{2}\right)[/tex]
On comparing both sides, we get
[tex]\dfrac{-6+a}{2}=-4[/tex]
[tex]-6+a=-8[/tex]
[tex]a=-8+6[/tex]
[tex]a=-2[/tex]
And,
[tex]\dfrac{-7+b}{2}=2[/tex]
[tex]-7+b=4[/tex]
[tex]b=4+7[/tex]
[tex]b=11[/tex]
Therefore, the coordinates of point B are (-2,11).