Question

A cube of iron and a cube of wood, each having a volume of V = 3.25 10-4 m3, are each placed in a large beaker of water. The density of the wood is rhowood = 3.73 102 kg/m3 and the density of the iron is rhoiron = 7.86 103 kg/m3. Calculate the buoyant force on each. (The cube of wood is allowed to float at the surface.)

Answer 1

Answer:

anor277

Nov 17, 2017

Well, by definition,

Molarity

≡

Moles of solute

Volume of solution

Explanation:

And thus...

moles of solute

=

molarity

×

volume

We use a molar quantity of

80.3

⋅

g

174.01

⋅

g

⋅

m

o

l

−

1

=

0.461

⋅

m

o

l

with respect to

potassium sulfate

And thus

volume

=

moles of solute

molarity

80.3

⋅

g

174.01

⋅

g

⋅

m

o

l

−

1

3.12

⋅

m

o

l

⋅

L

−

1

=

0.148

⋅

L

.

Answer 2

The buoyant force is one that acts against the weight of an object suspended in a fluid. The value of the buoyant force on each are:

i. Buoyant force on the cube of iron = 25.0 N

ii. Buoyant force on the cube of wood = 1.20 N

Upthrust is a force which acts against the direction of the weight of an object when suspended in a fluid. It acts majorly upwards against gravity, and it can be referred to as a buoyant force.

The amount of upthrust on object in a fluid sometimes depends on the density, volume and gravity acting on the object.

So that;

Upthrust = density x volume x gravity

Thus from the given question;

i. The buoyant force on the cube of iron can be determined by:

Upthrust = 7.86 x $10^{3}$ * 3.25 x $10^{-4}$ * 9.8

              =  25.034

Upthrust = 25.0 N

Therefore, the buoyant force on the cube of iron is 25.0 N.

ii. The buoyant force on the cube of wood can be determined by:

Upthrust = 3.73 x $10^{2}$ * 3.25 x $10^{-4}$ * 9.8

              = 1.1880

Upthrust = 1.20 N

Therefore, the buoyant force on the cube of wood is 1.20 N.

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