Respuesta :

Note: Your equation seems a little unclear. But, I am assuming that your equation is:

[tex]e^x\:+\:e^{-1}=\:2[/tex]

Because my solution would still clear your concept about this topic, no matter what the question is.

Answer:

Please check the explanation.

Step-by-step explanation:

Given the equation

[tex]e^x\:+\:e^{-1}=\:2[/tex]

subtract [tex]e^{-1}[/tex] from both sides

[tex]e^x+e^{-1}-e^{-1}=2-e^{-1}[/tex]

[tex]e^x=2-\frac{1}{e}[/tex]

[tex]\ln \left(e^x\right)\:=\ln \:\left(2-\frac{1}{e}\right)[/tex]

[tex]\:x\cdot ln\left(e\right)=\ln \:\:\left(2-\frac{1}{e}\right)[/tex]

[tex]\:x\cdot 1=\ln \:\left(2-\frac{1}{e}\right)[/tex]       ∵ [tex]\:\:\ln \left(e\right)=1[/tex]

[tex]x=\ln \:\left(2-\frac{1}{e}\right)[/tex]    

[tex]x=0.5[/tex]

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