Note: Your equation seems a little unclear. But, I am assuming that your equation is:
[tex]e^x\:+\:e^{-1}=\:2[/tex]
Because my solution would still clear your concept about this topic, no matter what the question is.
Answer:
Please check the explanation.
Step-by-step explanation:
Given the equation
[tex]e^x\:+\:e^{-1}=\:2[/tex]
subtract [tex]e^{-1}[/tex] from both sides
[tex]e^x+e^{-1}-e^{-1}=2-e^{-1}[/tex]
[tex]e^x=2-\frac{1}{e}[/tex]
[tex]\ln \left(e^x\right)\:=\ln \:\left(2-\frac{1}{e}\right)[/tex]
[tex]\:x\cdot ln\left(e\right)=\ln \:\:\left(2-\frac{1}{e}\right)[/tex]
[tex]\:x\cdot 1=\ln \:\left(2-\frac{1}{e}\right)[/tex] ∵ [tex]\:\:\ln \left(e\right)=1[/tex]
[tex]x=\ln \:\left(2-\frac{1}{e}\right)[/tex]
[tex]x=0.5[/tex]