1 (-2,2) Write the equation, in point-slope form, of the line that is perpendicular to the given line and passes through the point (-2, 2). * (4 Points)
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Answer:
y = -5x - 8
Step-by-step explanation:
Take the points (-5,-4) and (0,-3) plug them into this formula to get the slope.
[tex]\frac{y2 - y1 }{x2 - x1}[/tex]
Now plug in your points
[tex]\frac{-3 - (-4)}{0 - (-5)} \\\\\frac{1}{5}[/tex]
Since you're slope is 1/5 the slope of the perpendicular line is going to be the totally opposite -5 is the slope of the perpendicular line.
Now plug in -5 and the point (-2,2) into y = mx + b to get the y-intercept
2 = -5(-2) + b (b represents the y-intercept)
2 = 10 + b (subtract 10 from both sides)
-8 = b
The perpendicular line looks like this y = -5x - 8
Hope this helps ya! Keep smiling!