Question

2x^2+3x=(2x-1)(x+1)
Pls do explain

Answer 1

Answer:

$x=-\frac{1}{2}$

Step-by-step explanation:

You could solve this problem by either: Factoring or by using the Quadratic Formula.

SOLVING BY FACTORING STEPS

STEP 1: Move (2x−1)(x+1) to the left side of the equation by subtracting it from both sides.

$2x^2+3x-(2x-1)(x+1)=0$

STEP 2: Simplify 2x^2+3x−(2x−1)(x+1).

$2x+1=0$

STEP 3: Simplify each term.

$2x^2+3x-2x^2-x+1=0$

STEP 4: Simplify by adding terms.

$2x+1=0$

STEP 5: Subtract 1 from both sides of the equation.

$2x=-1$

STEP 6: Divide each term by 2 and simplify.

$x=-\frac{1}{2}$

SOLVE BY USING THE QUADRATIC FORMULA STEPS

STEP 1: Move all terms to the left side of the equation and simplify.

$2x+1=0$

STEP 2: Subtract 1 from both sides of the equation.

$2x=-1$

STEP 3: Divide each term by 2 and simplify.

$x=-\frac{1}{2}$

Answer 2

X= -1/2 hope this helps hehe :)