Question

In the right triangle below, the measure of angle C is 90°, AB= 5 units, and CB = 2 units. What is tan B? ​

Answer 1

It’s the letter F. Hope this helps

Answer 2

The value of the tanB is root of 21/2

We have given that ,

C is 90 degrees and side AB=5 units and CB=2 units

We have to find the tan B

We have given that the right angle triangle.

What is the value of tan ratio?

$tan\theta=\frac{opposite side}{adjucent side}$

Here opposite side side of B is AC and adjacent side of B  is CB.

We know the side AB=5 units and CB=2 units

First we have to find the side AC

Therefore by using Pythagoras theorem,

$AB^2=CB^2+AC^2$

$AB^2-CB^2=AC^2\\25-4=AC^2\\21=AC^2$

Taking square root on both side we have

$\sqrt{21}=AC\\ AC=\sqrt{21}$

Now we have the tan ratio,

$tan\theta=\frac{opposite side}{adjucent side}\\\\tanB=\frac{AC}{CB}\\\\tanB=\frac{\sqrt{21} }{2}$

Therefore the option F is correct.

The value of the tanB is root of 21/2.

To learn more about the trigonometric ratio visit:

https://brainly.com/question/24349828