Respuesta :
Given :
The dog runs 3.5 m/s in 15 s to chase the squirrel.
To Find :
The average rate of acceleration.
Solution :
Initial velocity, u = 0 m/s .
Final velocity, v = 3.5 m/s .
Time taken, t = 15 s.
We know, average acceleration is given by :
[tex]\text{Acceleration }= \dfrac{\text{Change in velocty}}{\text{Time Taken}}\\\\a = \dfrac{3.5-0}{15}\ m/s^2\\\\a = 0.23 \ m/s^2[/tex]
Therefore, average acceleration is 023 m/s².
Hence, this is the required solution.
The acceleration can be given as the rate of change of velocity with time. The acceleration of dog was 0.23 meter per second square.
What are the laws of motion?
The laws of motion are the three classical mechanics derived by Newton for the determination of motion of an object.
The first law of motion is given as;
[tex]v=u+at[/tex]
The initial speed of dog, [tex]u[/tex] is 0 m/s, as dog was at rest
The final speed of the dog was, [tex]v=3.5\;\rm m/s[/tex]
The time taken is, [tex]t=15\;\rm s[/tex]
Substituting the values for calculating the acceleration, [tex]a[/tex] of dog running,
[tex]\rm 3.5\;m/s=0\;m/s\;+\;\textit a\;\times\;15\;s\\3.5\;m/s-0\;m/s=15\textit a\\\textit a=0.23\;m/s^2[/tex]
The acceleration of dog was 0.23 meter per second square.
Learn more about acceleration, here:
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