Calculate the concentration of the resulting sodium oxalate solution if 0.1005 g of Na2C2O4 was used.

We can solve this problem finding molarity of sodium oxalate: That is, moles of Na2C2O4 per liter of solution. Thus, we need to convert the 0.1005g to moles using molar mass of sodium oxalate (134g/mol) and dividing in the 0.150L of the solution:

0.1005g * (1mol / 134g) = 7.5x10⁻⁴ moles of Na₂C₂O₄

In 0.150L:

7.5x10⁻⁴ moles of Na₂C₂O₄ / 0.150L =

0.00500M of Na₂C₂O₄

pstnonsonjoku pstnonsonjoku · Answer 2 · 2021-11-07T15:48:31+01:00

The concentration of the solution is 0.005 M.

From the information available in the question;

We know that;

Mass of Na2C2O4 = 0.1005 g

Volume of solution = 150 ml

To obtain the number of moles of Na2C2O4;

Number of moles = mass/molar mass

Molar mass of Na2C2O4 = 134 g/mol

Number of moles = 0.1005 g /134 g/mol = 0.00075 moles

Concentration = number of moles/volume

Volume of solution = 150ml or 0.15 L

Concentration = 0.00075 moles/0.15 L

= 0.005 M

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Missing parts

An acidic solution of sodium oxalate (Na2C2O4) was prepared by dissolving ~0.100 g of Na2C2O4 in 150 mL of 1.0 M H2SO4 in a 250 mL Erlenmeyer flask. Calculate the concentration of the resulting sodium oxalate solution if 0.1005 g of Na2C2O4 was used.