Write the balanced Ka and Kb reactions for HSO3- in water. Be sure to include the physical states of each species involved in the reaction.Ka:_________Kb:_________NOTE: Use the chemical equation editor tool to input the physical states. Do not subscript the physical states of the compounds.

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Answer:

Ka = [H₃O⁺] [SO₃²⁻] / [HSO₃⁻]

Kb = [OH⁻] [H₂SO₃] / [HSO₃⁻]

Explanation:

An amphoteric substance as HSO₃⁻ is a substance that act as either an acid or a base. When acid:

HSO₃⁻(aq) + H₂O(l) ⇄ H₃O⁺(aq) + SO₃²⁻(aq)

And Ka, the acid dissociation constant is:

Ka = [H₃O⁺] [SO₃²⁻] / [HSO₃⁻]

When base:

HSO₃⁻(aq) + H₂O(l) ⇄ OH⁻(aq) + H₂SO₃(aq)

And kb, base dissociation constant is:

Kb = [OH⁻] [H₂SO₃] / [HSO₃⁻]

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