Following the transformation of BCD to triangle B'C'D', only the signs of
the x and y values changes, the angle of rotation is therefore;
How can the angle of rotation of tringle BCD be found?
The coordinate of the point C on the preimage = (-2, 1)
The coordinate of the point C' on the image = (2, -1)
The difference in the coordinate is the change in the sign of the x and y
values.
The coordinate of a point (x, y) following a 180° rotation about the origin
is the point (-x, -y).
- [tex](x, \, y) \ \underrightarrow {180^{\circ} \ rotation} \ (-x, -y)[/tex]
Therefore;
- The angle of rotation of the preimage, triangle BCD to triangle B'C'D', is 180°
Learn more about rigid (rotational) transformation here:
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