Question

Use the diagram shown.

Which is a needed step to prove that △ABF≅△EDG?
∠BCD≅∠BCD

△CFG is isosceles.

line GF≅line GF

∠BCG≅∠DCF

Answer 1

Answer:

ΔCFG is an isosceles triangle.

Step-by-step explanation:

From the picture attached,

From ΔABF and ΔEDG,

Conditions for ΔABF and ΔEDG by SSS property of congruence,

1). AB ≅ DE [Given]

2). (BC + CF) = (DF + CG)

CF = CG [Given → BC = DF]

3). FA ≅ EG

(AG + GF) ≅ (EF + GF)

AG ≅ EF

Since, two sides of ΔCFG are equal in measure

ΔCFG is an isosceles triangle.

Answer 2

This can be determined by property of congruency. Hence, $\bold{2^{nd}}$option i.e. ΔCFG is an isosceles triangle is most appropriate.

Given :

From figure ΔABF and ΔEDG  are congruence by SSS property.

Proof:

From ΔABF and ΔEDG in figure,

Conditions for ΔABF and ΔEDG by SSS property of congruence,

1). AB ≅ DE [Given]

   (BC + CF) = (DC + CG)

2). BF≅DG

     CF = CG [Given → BC = CD]

3). FA ≅ EG

     (AG + GF) ≅ (EF + GF)

    AG ≅ EF

Therefore, two sides of ΔCFG are equal in measure.

Thus,ΔCFG is an isosceles triangle.

Hence, $\bold{2^{nd}}$ option i.e. ΔCFG is an isosceles triangle is most appropriate.

For further details,please prefer this link:

https://brainly.com/question/7830547