Given :
A 5-kg moving at 6 m/s collided with a 1-kg ball at rest.
The ball bounce off each other and the second ball moves in the same direction as the first ball at 10 m/sec.
To Find :
The velocity of the first ball after the collision.
Solution :
We know, by conservation of momentum :
[tex]m_1u_1 + m_2u_2 = m_1v_1 + m_2v_2[/tex]
Putting all given values with directions ( one side +ve and other side -ve ).
[tex]5\times 6 + 1\times 0 =5 \times v_1 + 1\times 10\\\\5v_1=10-30\\\\v = -4 \ m/s[/tex]
Therefore, the velocity of first ball after the collision is 4 m/s after in opposite direction.
Hence, this is the required solution.