Answer:
The equation of line passing through (10,9) and having slope 3/2 is: [tex]y = \frac{3}{2}x-6[/tex]
Step-by-step explanation:
The slope intercept form of a line is given by:
[tex]y=mx+b[/tex]
We are given
Slope = m = 3/2
Point = (10,9)
Putting the value of the slope in the equation we get
[tex]y = \frac{3}{2}x+b[/tex]
b is the y-intercept. To find the y-intercept we have to put the point through which the line passes in the equation.
Putting (10,9) in the equation
[tex]9 = \frac{3}{2}(10) +b\\9 = 15+b\\b = 9-15\\b = -6[/tex]
Putting b=-6 in the equation
[tex]y = \frac{3}{2}x-6[/tex]
Hence,
The equation of line passing through (10,9) and having slope 3/2 is: [tex]y = \frac{3}{2}x-6[/tex]
