Fill in the table so it represents a linear function.
X
5
10
15
20
25
y -1
11

Answer:
2; 5; 8
Step-by-step explanation:
To fill in the table, we need to generate an equation to represent the relationship between x and y.
First, find the slope using the two pairs given, (5, -1) and (25, 11):
[tex] slope (m) = \frac{y_2 - y_1}{x_2 - x_1} = \frac{11 -(-1)}{25 - 5} = \frac{12}{20} = \frac{3}{5} [/tex]
m = ⅗.
Next, using the point-slope form, we can use a point/coordinate pair and the slope to derive an equation as follows.
[tex] y - y_1 = m(x - x_1) [/tex]
Where,
[tex] x_1 = 5, y_1 = -1 [/tex]
m = ⅗.
Plug in the values
[tex] y -(-1) = \frac{3}{5}(x - 5) [/tex]
[tex] y + 1 = \frac{3}{5}(x - 5) [/tex]
[tex] y + 1 = \frac{3x}{5} - 3 [/tex]
Subtract 1 from both sides
[tex] y + 1 - 1 = \frac{3x}{5} - 3 - 1 [/tex]
[tex] y = \frac{3x}{5} - 4 [/tex]
Use the equation above to fill out the table by plugging each value of x into the equation to get the corresponding values of y for each x value.
✔️When x = 10:
[tex] y = \frac{3x}{5} - 4 [/tex]
[tex] y = \frac{3(10)}{5} - 4 = 6 - 4 [/tex]
[tex] y = 2 [/tex]
✔️When x = 15:
[tex] y = \frac{3x}{5} - 4 [/tex]
[tex] y = \frac{3(15)}{5} - 4 = 9 - 4 [/tex]
[tex] y = 5 [/tex]
✔️When x = 20:
[tex] y = \frac{3x}{5} - 4 [/tex]
[tex] y = \frac{3(20)}{5} - 4 = 12 - 4 [/tex]
[tex] y = 8 [/tex]