Question

Part a: if (6^2)^x = 1, the value of x is 0. the reason for it being 0 is because anything to the power of 0 equals 1. part b: if (6^0)^x = 1, then the value of x here is also ________

Answer 1

The value of x is all real numbers because 6^0 is 1 and 1 raised to the power of any number will still be 1.