The reflection mapping of the equation p(-2, 4) is [tex]\mathbf{R_{y =1}(P)=(-2,-2)}[/tex]
To solve this question, we must understand what is reflection mapping is all about.
In mathematical concepts, a reflection is indeed a mapping via a Euclidean plane to itself. The isometry of this usually has a hyperplane with designated fixed points that are commonly referred to as axis.
From the given information, we have:
The given points P = (-2, 4)
Required to find:
[tex]\mathbf{R_{y =1}(P)}[/tex]
Hence, the image of P under the axis(point of reflection line) is y = 1
Thus,
[tex]\mathbf{(x,y) = (x,2k-y)}[/tex]
[tex]\mathbf{(x,y) = (-2,2(1)-4)}[/tex]
[tex]\mathbf{(-2,4) = (-2,-2)}[/tex]
Therefore, we can conclude that the [tex]\mathbf{R_{y =1}(P)=(-2,-2)}[/tex]
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