Answer:
Heat transfer q = 664015.5 J/kg (Approx)
Explanation:
Given:
Area = a
Velocity flow rate Q1 = 87a m³/s
Velocity flow rate Q2 = 360a m³/s
Find:
Heat transfer = q
Computation:
[P1][v1]/T1 = [P2][v2]/T2
[2][(87a]/300 = [1.45][360a] / T2
T2 = 900 K
Heat transfer q = Cp(T2 - T1) + (V2² /2 - V1² /2 )
Heat transfer q = 1,005(900 - 300) + (360² /2 - 87² /2)
Heat transfer q = 664015.5 J/kg (Approx)