Please see below solution:
The electric field just outside its surface is
=
2
,
where is a radius of sphere, is a charge of sphere, =
1
4ε0
.
The electric field is
=
1
4ε0
2 =
1
ε0
∙
=
σ
ε0
,
where = 4
2
is an area of sphere, σ =
Q
S
is a surface charge density.
Answer:
.