Question

When the volume of a gas increases, is the work done by the gas on its surroundings positive, negative, or zero?
a.zero
b.negative
c.positive

Answer 1

Answer:

b.negative

Explanation:

The expression for the calculation of work done by the system on the surroundings is shown below as:

$w=-P\times \Delta V$

Where, P is the pressure

$\Delta V$ is the change in volume

From the question,

The volume of the gas increases which means that:- $\Delta V>0$

So,

Work done will be negative according to the above expression.