Respuesta :
I will use capital letters to represent vectors.
To find a vector (magnitude + direction):
R = A + B
To find only the direction of the vector:
theta = tan^-1(ycomponent/xcomponent)
To find the magnitude only ( your question)
R^2 = A^2 + B^2
R = sqrt( A^ 2 + B^2) (last option: D)
To find a vector (magnitude + direction):
R = A + B
To find only the direction of the vector:
theta = tan^-1(ycomponent/xcomponent)
To find the magnitude only ( your question)
R^2 = A^2 + B^2
R = sqrt( A^ 2 + B^2) (last option: D)
The magnitude of the resulting vector can be calculated by Pythagorean theorem.
Given Here,
A and B are two vectors,
R - magnitude of resulting vector.
Vector:
Pythagorean theorem can be applied to calculate the magnitude of the vector because the line joining the tow vector form a triangle.
It is a unit that has both magnitude and direction.
R = A + B
The magnitude of the resulting vector,
[tex]\bold {R^2 = A^2 + B^2}\\\\\bold {R = \sqrt( A^ 2 + B^2)}[/tex]
Therefore, the magnitude of the resulting vector can be calculated by Pythagorean theorem.
To know more about Vector quantity,
https://brainly.com/question/21797532