Question

A ballon has a volume of 5.6L at 25C and it is placed into liquid nitrogen at a temp of -78c. what is the volume of the ballon

Answer 1

Answer:

3.7L

Explanation:

Given parameters:

Initial volume  = 5.6L

Initial temperature  = 25°C = 273 + 25 = 298K

Final temperature = -78°C = 273 + (-78) = 195K

Unknown:

New volume of the balloon = ?

Solution:

We are going to assume that the pressure is constant and then we apply the charles's law;

  "the volume of fixed mass of a gas varies directly as its absolute temperature if its pressure is constant"

 mathematically;

         $\frac{V_{1} }{T_{1} }$   = $\frac{V_{2} }{T_{2} }$

Where V and T are temperature

            1 and 2 are initial and final states

Insert the parameters and solve;

       $\frac{5.6}{298}$  = $\frac{V_{2} }{195}$

      298V₂  = 1092

              V₂  = 3.7L