Question

how do I do this ? & how do I solve it for X&Y

Answer 1

Simple....

you have:

4x+3y≤-12

To solve for X or Y just isolate the variable....

4x+3y≤-12
    -3y    -3y

4x≤-3y-12

Now divide by 4....

$\frac{4x}{4} \leq \frac{-3y-12}{4}$

$x \leq -\frac{3y}{4} -3$

Now for y:

4x+3y≤-12

4x+3y≤-12
-4x          -4x

3y≤-4x-12

Divide by 3...

$\frac{3y}{3} \leq \frac{-4x-12}{3}$

$y \leq -\frac{4x}{3} -4$

This is the way to solve it.

Thus, your answer.