Respuesta :
E={1,2,3}
F={101,102,103,104}
There aren't the same numbers in set E and set F. So
[tex]E \cap F = \emptyset \qquad \hbox{(empty set)}[/tex]
F={101,102,103,104}
There aren't the same numbers in set E and set F. So
[tex]E \cap F = \emptyset \qquad \hbox{(empty set)}[/tex]
Answer:
The correct option is 1.
Step-by-step explanation:
The given sets are
E = {1, 2, 3}
F = {101, 102, 103, 104}
The intersection of two events represent the common element of both the sets.
It is clear that, there are no common elements in set E and F, therefore the intersection of both E and F is null set or empty set.
[tex]E\cap F=\phi[/tex]
[tex]E\cap F=\{\}[/tex]
Therefore the correct option is 1.